室温下,将1mol的CuS04?5H:O(s)溶于水会使溶液温度降低,热效应为△H1。,将1mol的CuS04。(s)溶于水会使溶液温度升高,热效应为△H...

作者: tihaiku 人气: - 评论: 0
问题 室温下,将1mol的CuS04?5H:O(s)溶于水会使溶液温度降低,热效应为△H1。,将1mol的CuS04。(s)溶于水会使溶液温度升高,热效应为△H2;CHS04?5H20受热分解的化学方程式为:
选项 A.△H2>△H3 B.△H1<△H3 C.△H1+△H3=△H2 D.△H1+△H2=△H3
答案 B
解析 根据题意,发生反应的热化学方程式为: CuS0?5H2O(S)溶于水f溶液温度降低.该过程为吸热过程). 根据盖斯定律可知:△H,=△Hl一△H2>0;A项,根据上述分析,△2<0,△H3>0,所以A项错误;B项,△H3=AH广△H2(△H2<0),所以△H3>△Hl,B项正确;C项,△H3=△H1-△H2,C项错误;D项,△Hl+△H2<△H3,D项错误。故选B。

相关内容:室温,溶液,温度,热效

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