已知向量a=(3cosα,3sinα),b=(2cosβ,2sinβ),若a与b的夹角为60°,则直线 与圆(X-cosβ)2+(Y-sin...

作者: tihaiku 人气: - 评论: 0
问题 已知向量a=(3cosα,3sinα),b=(2cosβ,2sinβ),若a与b的夹角为60°,则直线 与圆(X-cosβ)2+(Y-sinβ)2=1的位置关系是( )。
选项 A.相交且不过圆心 B.相交且过圆心 C.相切 D.相离
答案 C
解析
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