曲线y＝X2+4在(0，4)处的法线方程为( )。A.y=0 B.y=4 C.x=0 D.x=4

作者: tihaiku 人气: - 评论: 0

问题曲线y＝X2+4在(0，4)处的法线方程为( )。

选项 A.y=0 B.y=4 C.x=0 D.x=4

答案 C

解析 f(x)＇＝2x，故f＇(0)=0，切线斜率为0，法线与切线相互垂直且过点(0，4)，故法线方程为x=0。

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曲线y＝X2+4在(0，4)处的法线方程为( )。A.y=0 B.y=4 C.x=0 D.x=4

相关内容：曲线,法线,方程

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