12 +22 +32 +…+ 1234567892 的个位数是()。A. 3 B. 4 C. 5 D. 6

作者: tihaiku 人气: - 评论: 0
问题 12 +22 +32 +…+ 1234567892 的个位数是()。
选项 A. 3 B. 4 C. 5 D. 6
答案 C
解析 本题采用尾数法。原式中12 + 22 +32 +…+ 102=1 + 4 + 9 +…+ 100,算得尾数为5,由此可以推知原式所算出结果的个位数应为5的倍数,即5或者0。选项中只有C选项满足,故正确答案为C。

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