甲杯盛有100克纯酒精,乙杯盛有100克纯水,将甲杯中纯酒精倒入乙杯若干克,混合后再將乙杯中溶液倒入甲杯若干克,使两杯溶液仍各有100克,此时测得甲杯中有...

作者: tihaiku 人气: - 评论: 0
问题 甲杯盛有100克纯酒精,乙杯盛有100克纯水,将甲杯中纯酒精倒入乙杯若干克,混合后再將乙杯中溶液倒入甲杯若干克,使两杯溶液仍各有100克,此时测得甲杯中有20克水,求乙杯中酒精占溶液的几分之几?( ) A. 30% B. 25% C. 20% D. 15%
选项
答案 C
解析 最后甲中有20克水,表明甲中有100-20 = 80(克)酒精,此时乙中有酒精100-80=20(克),它占溶液20 /100 =1/5。

相关内容:甲杯,100克,酒精,乙杯,纯水,杯中,混合,將乙,溶液,两杯

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