曲线y=3x+1在点(1，3)处的切线方程为( )。A、y=2x+1 B、r=4x-1 C、y=4x+2 D、y=3x

作者: tihaiku 人气: - 评论: 0

问题曲线y=3x+1在点(1，3)处的切线方程为( )。

选项 A、y=2x+1 B、r=4x-1 C、y=4x+2 D、y=3x

答案 B

解析先求出y=x3+1在点(1，3)处切线的斜率为4，再根据过(1，3)，得到切线方程为y=4x-l。

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消息: [程序异常] : MISCONF Redis is configured to save RDB snapshots, but it's currently unable to persist to disk. Commands that may modify the data set are disabled, because this instance is configured to report errors during writes if RDB snapshotting fails (stop-writes-on-bgsave-error option). Please check the Redis logs for details about the RDB error.

文件: /twcms/kongphp/cache/cache_redis.class.php

位置: 第 85 行

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曲线y=3x+1在点(1，3)处的切线方程为( )。A、y=2x+1 B、r=4x-1 C、y=4x+2 D、y=3x

相关内容：曲线,在点,切线,方程

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