设a,b均为正整数,若11a+7b=84,则a的值为( )A.4 B.5 C.7 ...

作者: tihaiku 人气: - 评论: 0
问题 设a,b均为正整数,若11a+7b=84,则a的值为( )
选项 A.4 B.5 C.7 D.8
答案 C
解析 C。不定方程求解,可分析未知数所应满足的倍数特征。84是7的倍数,而7b肯定是7的倍数,所以11a也是7的倍数,所以a=7。

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