一辆公交车从甲地开往乙地需经过三个红绿灯路口,在这三个路口遇到红灯的概率分别是0.4、0.5、0.6,则该车 从甲地开往乙地遇到红灯的概率是A.0.12...

作者: tihaiku 人气: - 评论: 0
问题 一辆公交车从甲地开往乙地需经过三个红绿灯路口,在这三个路口遇到红灯的概率分别是0.4、0.5、0.6,则该车 从甲地开往乙地遇到红灯的概率是
选项 A.0.12 B.0.50 C.0.88 D.0.89
答案 C
解析 逆向思维,都没有遇到红灯的概率为0.4*0.5*0.6=0.12,答案为1-0.12=0.88

相关内容:公交车,甲地,乙地,三个,红绿灯,路口,红灯,概率,A.0.12...

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