已知函数f(x)=㏑(x+2)-x2+bx+c, (1)若点P(-1,0)在f(x)的图象上,过点P的切线与直线y=-x+2平行,求f(x)的解析式;...

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问题 已知函数f(x)=㏑(x+2)-x2+bx+c, (1)若点P(-1,0)在f(x)的图象上,过点P的切线与直线y=-x+2平行,求f(x)的解析式; (2)若f(x)在区间[0,2]上单调递增,求b的取值范围。
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相关内容:函数,-x2+bx+c,若点,图象,过点,切线,直线,平行

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